N-Queens/Sudoku Assignment

Motivation

Not everything in the world should be divided and conquered. Backtracking is a powerful technique which can be readily parallelized. We will gain experience with backtracking by solving the N-Queens problem and Sudoku in parallel.

N-Queens in particular can be used to explain the call stack as the chessboard *IS* the call stack. Whoa.

Further, by employing constraint propagation and search we can dramatically improve performance for problems like Sudoku.

Background

The n-queens problem is a fundamental coding puzzle which asks: how can N queens be placed on an NxN chessboard so that they cannot attack each other? In chess, a queen can move horizontally, vertically, and diagonally across the board. Thus, to solve the n-queens problem, we must effectively figure out how to place the queens in such a way that no two of them occupy the same row, column, or diagonal.

We will be using a similar algorithm to solve a Sudoku puzzle. A Sudoku puzzle is composed of a 9-by-9 grid of squares. This grid is also divided into 9 large boxes, each of which is a 3-by-3 of the smaller squares. In a completed puzzle, each of the smaller squares contains a single number from 1 to 9 (inclusive). However, if a square contains a given number, that same number cannot be anywhere else in the same row, column, or box. Thus, for Sudoku, we are given an incomplete board and must fill in the remaining squares while meeting these requirements. For more explanation, take a look at Peter Norvig's essay about solving Sudoku.

In this assignment, you will implement solutions to both the n-queens and Sudoku problems.

Code To Implement

N-Queens

Sequential Solution

class:	DefaultImmutableQueenLocations .java
methods:	createNext getColumnOfQueenInRow getRowCount getBoardSize isNextRowThreatFree
package:	nqueens.lab
source folder:	student/src/main/java

method: public DefaultImmutableQueenLocations createNext(int column) (sequential implementation only)

method: public int getColumnOfQueenInRow(int row) (sequential implementation only)

method: public int getRowCount() (sequential implementation only)

method: public int getBoardSize() (sequential implementation only)

method: public boolean isNextRowThreatFree(int column) (sequential implementation only)

DefaultImmutableQueenLocations

class:	DefaultImmutableQueenLocations.java
methods:	createNext getColumnOfQueenInRow getRowCount getBoardSize
package:	nqueens.lab
source folder:	student/src/main/java

method: private static void placeQueenInRow(MutableInt count, MutableQueenLocations queenLocations, int row) (sequential implementation only)

Tips

N-Queens

There are three classes you will need to modify: DefaultImmutableQueenLocations.java, SequentialNQueens.java, and ParallelNQueens.java. Start with QueenLocations and then we recommend moving on to the sequential solution before the parallel one. Take a look at the javadocs to see what everything does and what you will need to implement.

A couple of notes and common issues:

• As ImmutableQueenLocations is immutable, you will need to create a new instance of the object whenever you move on from one row to the next. This is where createNext comes in, along with the private constructor of this class.
• The isNextRowThreatFree method can easily be completed with a method in AbstractQueenLocations. Refer to that for help.
• The sequential solution uses MutableQueenLocations while the parallel solution uses your implementation of ImmutableQueenLocations. Be careful to use the correct QueenLocations implementation.
• As the name suggests, placeQueenInRow will go through the columns of the given row to check if a queen can fit in that location. If it can, it will set that value in MutableQueenLocations. If the examined row is that last row of the board, you have found one valid solution to the n-queens problem. Update the correct parameter accordingly. Otherwise, recurse and keep going until you reach the last row.
• For the parallel implementation of placeQueenInRow, we are using the "one-finish" pattern. Do not call finish in the recursive method.
• The syntax for instantiating a FinishAccumulator of Integer is: FinishAccumulator<Integer> acc = newIntegerFinishAccumulator(NumberReductionOperator.SUM);
• The syntax for using a FinishAccumulator is: finish(register(acc), () -> { //body });

Sudoku

Coming Soon

Testing Your Solution

Visualization

N-Queens

class:	NQueensVizApp.java	VIZ
package:	nqueens.viz.solution
source folder:	student/src//java

Sudoku

class:	SudokuSolutionApp.java	VIZ
package:	sudoku.viz.solution
source folder:	student/src//java

Correctness

There is a top-level test suite comprised of sub test suites which can be invoked separately when you want to focus on one part of the assignment.

top level

class:	BacktrackTestSuite.java
package:	backtrack.lab
source folder:	testing/src/test/java

sub

class:	NQueensTestSuite.java
package:	nqueens.lab
source folder:	testing/src/test/java

class:	SudokuTestSuite.java
package:	sudoku.lab
source folder:	testing/src/test/java

Rubric

As always, please make sure to cite your work appropriately.

Total points: 100

N-Queens subtotal: 40

• Correct ImmutableQueenLocations (10)
• Correct sequential implementation (10)
• Correct parallel implementation (20)

Sudoku subtotal: 50

• Correct ImmutableSudokuPuzzle (10)
• Correct SquareSearchAlgorithm (15)
• Correct ParallelSudoku (25)

Whole project:

• Clarity and efficiency (10)