The maximum displacement in this problem is 332.04. The computed displacements in both problems match this value, and the displacements at the other nodes match as well.

The maximum displacement of –2.0E–4 occurs at nodes 3 and 7 in this problem. Both runs have identical displacement fields.

The temperature variation through the plate in this example is the same at all nodes. The bottom has a temperature of 0.0, the middle temperature is 746.0, and the top has a temperature of 994.7. The results for both cases are the same.

The temperature variation through the plate in this example is the same at all nodes. The bottom has a temperature of 0.0, the middle temperature is 746.2, and the top has a temperature of 994.69. The results for both runs are the same.

The maximum displacement of –8.6667E–5 occurs at node 4 in both problems. However, the problem which uses the previously computed matrices is missing the rotation at node 1. This extra degree of freedom in the first run is a result of special procedures that activate the rotation if a boundary or loading condition is applied there. The precomputed element stiffness matrix does not have this capability.

The maximum displacement of –8.6667E–5 occurs at node 4 in both problems. Both runs have identical displacement fields, including the rotations. There is no conditional activation of rotation degrees of freedom with the S4 elements as there is with the S4R5 elements.

The maximum displacement of –8.6667E–5 occurs at node 4 in both problems. Both runs have identical displacement fields, including the rotations. There is no conditional activation of rotation degrees of freedom with the S4R elements, as there is with the S4R5 elements.

The maximum displacement of –3.6376 occurs at node 89. Both runs have the same displacements.